A body is executing simple harmonic motion. At a displacement $x$ its potential energy is $E_1$ and at a displacement $y$ its potential energy is $E_2$. The potential energy $E$ at a displacement $(x+y)$ is
- A$\sqrt{E}=\sqrt{E_1}-\sqrt{E_2}$
- B$\sqrt{E}=\sqrt{E_1}+\sqrt{E_2}$
- C$E=E_1-E_2$
- D$E+E_1+E_2$
✓ Correct answer: B
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