A capacitor with plate separation \(d\) is charged to \(V\) volts. The battery is disconnected and a dielectric slab of thickness \(d/2\) and dielectric constant '2' is inserted between the plates. The potential difference across its terminals becomes
- A\(V\)
- B\(2V\)
- C\(\frac{4V}{3}\)
- D\(\frac{3V}{4}\)
✓ Correct answer: D
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