A magnet hung at $$45^{\circ}$$ with magnetic meridian makes an angle of $$60^{\circ}$$ with the horizontal. The actual value of the angle of dip is -
- A$$\tan ^{-1}\left(\sqrt{\frac{3}{2}}\right)$$
- B$$\tan ^{-1}(\sqrt{6})$$
- C$$\tan ^{-1}\left(\sqrt{\frac{2}{3}}\right)$$
- D$$ \tan ^{-1}\left(\sqrt{\frac{1}{2}}\right) $$
✓ Correct answer: A
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