A particle of mass m is projected with a velocity u making an angle $$\theta$$ with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height is
- A0
- B$$\frac{m u \sin ^2 \theta \cos \theta}{2 g}$$
- C$$\frac{2 m u^2 \cos ^2 \theta \sin \theta}{g}$$
- D$$\frac{m u^3 \sin ^2 \theta \cos \theta}{2 g}$$
✓ Correct answer: D
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