A particle starts from rest and moves in a straight line. It travels a distance $2 L$ with uniform acceleration and then moves with a constant velocity a further distance of $L$. Finally, it comes to rest after moving a distance of $3 L$ under uniform retardation. Then, the ratio of average speed to the maximum speed $\left(\frac{v}{v_m}\right)$ of the particle is
- A$\frac{6}{11}$
- B$\frac{7}{11}$
- C$\frac{5}{11}$
- D$\frac{2}{11}$
✓ Correct answer: A
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