An inductor coil wound uniformly has self inductance 'L' and resistance 'R'. The coil is broken into two identical parts. The two parts are then connected in parallel across a battery of 'E' volt of negligible internal resistance. The current through battery at steady state is
- A$$\mathrm{\frac{2E}{R}}$$
- B$$\mathrm{\frac{3E}{R}}$$
- C$$\mathrm{\frac{4E}{R}}$$
- D$$\mathrm{\frac{E}{R}}$$
✓ Correct answer: C
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