$x^2+y^2+2 x-6 y-6=0$ and $x^2+y^2-6 x-2 y+k=0$ are two intersecting circles and $k$ is not an integer. If $ heta$ is the angle between the two circles and $\cos heta=\frac{-5}{24}$, then $k=$

Question

$x^2+y^2+2 x-6 y-6=0$ and $x^2+y^2-6 x-2 y+k=0$ are two intersecting circles and $k$ is not an integer. If $	heta$ is the angle between the two circles and $\cos 	heta=\frac{-5}{24}$, then $k=$

Accepted Answer

Correct answer: B

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