At 298 K , if the standard Gibbs energy change $\Delta_r G^{\circ}$ of a reaction is -115 kJ , the value of $\log _{10} K_p$ will be $\left(R=8.314 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\right)$
- A
+20.15
- B
-20.15
- C
-10.30
- D
+10.30
✓ Correct answer: A
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