Bag I contains 3 red, 4 black and 3 white balls and Bag II contains 2 red, 5 black and 2 white balls. One ball is transferred from Bag I to Bag II and then a ball is drawn from Bag II. The ball so drawn is found to be black in colour. Then the probability, that the transferred ball is red, is :
- A$$\frac{4}{9}$$
- B$$\frac{5}{18}$$
- C$$\frac{1}{6}$$
- D$$\frac{3}{10}$$
✓ Correct answer: B
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