Based on the values of B.E. given, ΔH°f of N₂H₄(g) is: Given: N–N = 159 kJ mol⁻¹; H–H = 436 kJ mol⁻¹; N≡N = 941 kJ mol⁻¹; N–H = 398 kJ mol⁻¹
- A711 kJ mol⁻¹
- B62 kJ mol⁻¹
- C−98 kJ mol⁻¹
- D−711 kJ mol⁻¹
✓ Correct answer: B
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