Equal moles of benzene and toluene are mixed. The vapour pressures of benzene and toluene in pure state are $700$ and $600\,\mathrm{mm\,Hg}$ respectively. The mole fraction of benzene in vapour state is
- A$0.7$
- B$0.47$
- C$0.50$
- D$0.54$
✓ Correct answer: D
Want the full step-by-step reasoning?