For a gaseous reaction: A(g) + 3B(g) → 3C(g) + 3D(g) ΔE is 17 kcal at 27°C. Assuming R = 2 cal K⁻¹ mol⁻¹ the value of ΔH for the above reaction will be
- A15.8 kcal
- B16.4 kcal
- C18.2 kcal
- D20.0 kcal
✓ Correct answer: C
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