$$\frac{d}{d x}\left[\tan ^{-1}\left(\frac{\cos x}{1+\sin x}\right)\right]$$ is equal to
- A$$\frac{1}{2}$$
- B$$\frac{-1}{2}$$
- C1
- D$$-$$1
✓ Correct answer: B
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NewNcert › mathematics › Continuity and Differentiability
$$\frac{d}{d x}\left[\tan ^{-1}\left(\frac{\cos x}{1+\sin x}\right)\right]$$ is equal to
Want the full step-by-step reasoning?
Question ID #140506 · NewNcert