If a charged spherical conductor of radius $10\,\text{cm}$ has potential $V$ at a point distant $5\,\text{cm}$ from its centre, then the potential at a point distant $15\,\text{cm}$ from the centre will be:
- A$\frac{V}{3}$
- B$\frac{2}{3}V$
- C$\frac{3}{2}V$
- D$3V$
✓ Correct answer: B
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