If $A=\left[\begin{array}{ll}1 & 1 \\ 0 & 1\end{array}\right]$ and $B=\left[\begin{array}{cc}\frac{\sqrt{3}}{2} & \frac{1}{2} \\ -\frac{1}{2} & \frac{\sqrt{3}}{2}\end{array}\right]$, then $\left(B B^T A\right)^5$ is equal to
- A$\left[\begin{array}{cc}2+\sqrt{3} & 1 \\ -1 & 2-\sqrt{3}\end{array}\right]$
- B$\frac{1}{2}\left[\begin{array}{ll}1 & 5 \\ 0 & 1\end{array}\right]$
- C$\left[\begin{array}{ll}1 & 5 \\ 0 & 1\end{array}\right]$
- D$\left[\begin{array}{ll}5 & 1 \\ 0 & 1\end{array}\right]$
✓ Correct answer: C
Want the full step-by-step reasoning?