If $3 x+6 y+2=0, x+y+1=0,2 x-y+3=0$ are three given lines, then the point $\left(\frac{-4}{3}, \frac{1}{3}\right)$ is
- A
the orthocentre of the triangle formed by the lines
- B
the point of concurrence of the lines
- C
the circumcentre of the triangle formed by the lines
- D
the incentre of the triangle formed by the lines
✓ Correct answer: B
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