If $y=(\log x)^{1 / x}+x^{\log x}$, at $x=e, \frac{d y}{d x}=$
- A
$2+\frac{1}{e}$
- B
$e^2+\frac{1}{2}$
- C
$\frac{1}{e^2}+2$
- D
$e+\frac{1}{e}$
✓ Correct answer: C
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NewNcert › mathematics › Continuity and Differentiability
If $y=(\log x)^{1 / x}+x^{\log x}$, at $x=e, \frac{d y}{d x}=$
$2+\frac{1}{e}$
$e^2+\frac{1}{2}$
$\frac{1}{e^2}+2$
$e+\frac{1}{e}$
Want the full step-by-step reasoning?
Question ID #140466 · NewNcert