If for a positive integer n, the quadratic equation
$$x\left( {x + 1} \right) + \left( {x + 1} \right)\left( {x + 2} \right)$$$$ + .... + \left( {x + \overline {n - 1} } \right)\left( {x + n} \right)$$$$ = 10n$$
has two consecutive integral solutions, then n is equal to :
$$x\left( {x + 1} \right) + \left( {x + 1} \right)\left( {x + 2} \right)$$$$ + .... + \left( {x + \overline {n - 1} } \right)\left( {x + n} \right)$$$$ = 10n$$
has two consecutive integral solutions, then n is equal to :
- A9
- B10
- C11
- D12
✓ Correct answer: C
Want the full step-by-step reasoning?