If $\mathrm{f}(x)=\frac{1+\cos \pi x}{\pi(1-x)^2}$, for $x \neq 1$ is continuous at $x=1$, then $\mathrm{f}(1)$ is equal to
- A$\frac{\pi}{2}$
- B$\frac{2}{\pi}$
- C$\frac{\pi^2}{4}$
- D$\frac{4}{\pi^2}$
✓ Correct answer: A
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