If $\left[\begin{array}{ccc}0 & 2 & a \\ b & 0 & 4 \\ -3 & c & 0\end{array}\right]$ is a skew-symmetric matrix, then $\left[\begin{array}{ll}a & b \\ b & a\end{array}\right]\left[\begin{array}{ll}b & c \\ c & b\end{array}\right]=$
- A
$\left[\begin{array}{ll}0 & 0 \\ 0 & 0\end{array}\right]$
- B
$\left[\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right]$
- C
$\left[\begin{array}{cc}2 & -8 \\ -8 & 2\end{array}\right]$
- D
$\left[\begin{array}{ll}2 & 8 \\ 8 & 2\end{array}\right]$
✓ Correct answer: C
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