If the electronic configuration of an element is $[\mathrm{Kr}]5s^2 4d^{10} 5p^2$ then the element belongs to
- A4$^{\mathrm{th}}$ period, 4$^{\mathrm{th}}$ group
- B4$^{\mathrm{th}}$ period, 14$^{\mathrm{th}}$ group
- C5$^{\mathrm{th}}$ period, 4$^{\mathrm{th}}$ group
- D5$^{\mathrm{th}}$ period, 14$^{\mathrm{th}}$ group
✓ Correct answer: D
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