If the lines $x+y-1=0, k x+2 y+1=0$ and $4 x+2 k y+7=0$ are concurrent, then $k=$
- A
2
- B
$\frac{13}{2}$
- C
$\frac{-13}{2}$
- D
-2
✓ Correct answer: C
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NewNcert › mathematics › Straight Lines And Pair Of Straight Lines
If the lines $x+y-1=0, k x+2 y+1=0$ and $4 x+2 k y+7=0$ are concurrent, then $k=$
2
$\frac{13}{2}$
$\frac{-13}{2}$
-2
Want the full step-by-step reasoning?
Question ID #184720 · NewNcert