If the mean and variance of a binomial distribution are $\frac{4}{3}$ and $\frac{10}{9}$ respectively, then $P(X \geq 6)=$
- A
$\frac{41}{6^8}$
- B
$\frac{741}{6^8}$
- C
$1-\frac{741}{6^8}$
- D
$1-\frac{41}{6^8}$
✓ Correct answer: B
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