If the probability that the random variable $$\mathrm{X}$$ takes values $$x$$ is given by $$\mathrm{P}(\mathrm{X}=x)=\mathrm{k}(x+1) 3^{-x}, x=0,1,2,3, \ldots$$, where $$\mathrm{k}$$ is a constant, then $$\mathrm{P}(\mathrm{X} \geq 2)$$ is equal to :

A$$\frac{7}{18}$$

B$$\frac{20}{27}$$

C$$\frac{7}{27}$$

D$$\frac{11}{18}$$

✓ Correct answer: C

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Question

If the probability that the random variable $$\mathrm{X}$$ takes values $$x$$ is given by $$\mathrm{P}(\mathrm{X}=x)=\mathrm{k}(x+1) 3^{-x}, x=0,1,2,3, \ldots$$, where $$\mathrm{k}$$ is a constant, then $$\mathrm{P}(\mathrm{X} \geq 2)$$ is equal to :

A$$\frac{7}{18}$$
B$$\frac{20}{27}$$
C$$\frac{7}{27}$$
D$$\frac{11}{18}$$

✓ Correct answer: C

Want the full step-by-step reasoning?

Accepted Answer

Correct answer: C

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