If the solution for the differential equation $y^2 d x+\left(x^2-x y-y^2\right) d y=0$ at $(2,1)$ is $x+y=k\left(x y^2-y^3\right)$, then $k=$
- A
-3
- B
-4
- C
4
- D
3
✓ Correct answer: A
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If the solution for the differential equation $y^2 d x+\left(x^2-x y-y^2\right) d y=0$ at $(2,1)$ is $x+y=k\left(x y^2-y^3\right)$, then $k=$
-3
-4
4
3
Want the full step-by-step reasoning?
Question ID #184035 · NewNcert