If the system of simultaneous linear equations $x-2 y+z=0,2 x+3 y+z=6$ and $x+2 y+p z=q$ has infinitely many solutions, then
- A
$p+q=4$
- B
$p q=\frac{48}{49}$
- C
$q-p=3$
- D
$\frac{p}{q}=4$
✓ Correct answer: C
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If the system of simultaneous linear equations $x-2 y+z=0,2 x+3 y+z=6$ and $x+2 y+p z=q$ has infinitely many solutions, then
$p+q=4$
$p q=\frac{48}{49}$
$q-p=3$
$\frac{p}{q}=4$
Want the full step-by-step reasoning?
Question ID #183418 · NewNcert