If $y=\sqrt{\cosh x+\sqrt{\cosh x}}$, then $\frac{d y}{d x}=$
- A
$\frac{\sinh x\left(2 y^2+2 \cosh x+1\right)}{4 y\left(y^2+\cosh x\right)}$
- B
$\frac{\sinh x\left(2 y^2-2 \cosh x-1\right)}{4 y\left(y^2-\cosh x\right)}$
- C
$\frac{\sinh x(1-2 \sqrt{\cosh x})}{4 y \sqrt{\cosh x}}$
- D
$\frac{\sinh x(1+2 \sqrt{\cosh x})}{4 y \sqrt{\cosh x})}$
✓ Correct answer: D
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