If $A=\left[\begin{array}{lll}1 & 5 & 2 \\ 4 & 1 & 3 \\ 2 & 6 & 3\end{array}\right]$, then $\left|(\operatorname{adj} A)^{-1}\right|=$
- A
-1
- B
1
- C
4
- D
-4
✓ Correct answer: B
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NewNcert › mathematics › Matrices And Determinants
If $A=\left[\begin{array}{lll}1 & 5 & 2 \\ 4 & 1 & 3 \\ 2 & 6 & 3\end{array}\right]$, then $\left|(\operatorname{adj} A)^{-1}\right|=$
-1
1
4
-4
Want the full step-by-step reasoning?
Question ID #183421 · NewNcert