In an isobaric process, when temperature changes from $T_1$ to $T_2$, $\Delta S$ is equal to
- A$2.303\,C_p\log\left(\frac{T_2}{T_1}\right)$
- B$2.303\,C_p\ln\left(\frac{T_2}{T_1}\right)$
- C$C_p\ln\left(\frac{T_1}{T_2}\right)$
- D$C_v\ln\left(\frac{T_2}{T_1}\right)$
✓ Correct answer: A
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