$$\int {{{{{\sin }^8}x - {{\cos }^8}x} \over {1 - 2{{\sin }^2}x{{\cos }^2}x}}dx} $$
- A$$ - {1 \over 2}\sin 2x + C$$
- B$${1 \over 2}\sin 2x + C$$
- C$${1 \over 2}\sin x + C$$
- D$$ - {1 \over 2}\sin x + C$$
✓ Correct answer: A
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