$$\int {\sqrt {1 + \cos x} dx} $$ is equal to
- A$$2\sqrt 2 \cos {x \over 2} + C$$
- B$$2\sqrt 2 \sin {x \over 2} + C$$
- C$$\sqrt 2 \cos {x \over 2} + C$$
- D$$\sqrt 2 \sin {x \over 2} + C$$
✓ Correct answer: B
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$$\int {\sqrt {1 + \cos x} dx} $$ is equal to
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Question ID #187887 · NewNcert