Let $\alpha, \beta$ and $\gamma$ be real numbers.
If $\left[\begin{array}{ccc}7 & 5 & \alpha \ \beta & 2 & 11 \ 3 & \gamma & 1\end{array} ight]\left[\begin{array}{l}1 \ 3 \ 2\end{array} ight]=\left[\begin{array}{c}\alpha+\beta \ -2 \alpha+\beta-2 \gamma \ \alpha+2 \beta+3 \gamma\end{array} ight]$, then $100+\frac{2 \alpha+11 \beta}{\gamma}=$

Question

Let $\alpha, \beta$ and $\gamma$ be real numbers.
If $\left[\begin{array}{ccc}7 & 5 & \alpha \ \beta & 2 & 11 \ 3 & \gamma & 1\end{array}ight]\left[\begin{array}{l}1 \ 3 \ 2\end{array}ight]=\left[\begin{array}{c}\alpha+\beta \ -2 \alpha+\beta-2 \gamma \ \alpha+2 \beta+3 \gamma\end{array}ight]$, then $100+\frac{2 \alpha+11 \beta}{\gamma}=$

Accepted Answer

Correct answer: A

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