Let $x = x(y)$ be the solution of the differential equation $2y^2 \frac{dx}{dy} - 2xy + x^2 = 0$, $y > 1$, $x(e) = e$.
Then $x(e^2)$ is equal to:
- A
$\frac{3}{2} e^2$
- B
$\frac{2}{3} e^2$
- C
$e^2$
- D
$2e^2$
✓ Correct answer: B
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