Let for $f(x)=7 an ^8 x+7 an ^6 x-3 an ^4 x-3 an ^2 x, \quad \mathrm{I}_1=\int_0^{\pi / 4} f(x) \mathrm{d} x$ and $\mathrm{I}_2=\int_0^{\pi / 4} x f(x) \mathrm{d} x$. Then $7 \mathrm{I}_1+12 \mathrm{I}_2$ is equal to :

Question

Let for $f(x)=7 	an ^8 x+7 	an ^6 x-3 	an ^4 x-3 	an ^2 x, \quad \mathrm{I}_1=\int_0^{\pi / 4} f(x) \mathrm{d} x$ and $\mathrm{I}_2=\int_0^{\pi / 4} x f(x) \mathrm{d} x$. Then $7 \mathrm{I}_1+12 \mathrm{I}_2$ is equal to :

Accepted Answer

Correct answer: B

More Definite Integration questions