Let $f(\theta)=\left|\begin{array}{ccc}1 & \cos \theta & -1 \\ -\sin \theta & 1 & -\cos \theta \\ -1 & \sin \theta & 1\end{array}\right|$. Suppose $A$ and $B$ are respectively maximum and minimum values of $f(\theta)$.Then $(A,B)$ is equal to
- A$(2,1)$
- B$(2,0)$
- C$(\sqrt{2}, 1)$
- D$\left(2, \frac{1}{\sqrt{2}}\right)$
✓ Correct answer: B
Want the full step-by-step reasoning?