Let the image of parabola $x^2=4 y$, in the line $x-y=1$ be $(y+a)^2=b(x-c)$, $a, b, c \in \mathrm{~N}$. Then $a+b+c$ is equal to
- A
12
- B
8
- C
6
- D
4
✓ Correct answer: C
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NewNcert › mathematics › Conic Sections
Let the image of parabola $x^2=4 y$, in the line $x-y=1$ be $(y+a)^2=b(x-c)$, $a, b, c \in \mathrm{~N}$. Then $a+b+c$ is equal to
12
8
6
4
Want the full step-by-step reasoning?
Question ID #165521 · NewNcert