LIST-I contains compounds and LIST-II contains reactions
| List-I | List-II |
|---|---|
| (I) $\mathrm{H}_{2} \mathrm{O}_{2}$ |
(P) $\mathrm{Mg}\left(\mathrm{HCO}_{3}\right)_{2}+\mathrm{Ca}(\mathrm{OH})_{2} \rightarrow$ |
| (II) $\mathrm{Mg}(\mathrm{OH})_{2}$ |
(Q) $\mathrm{BaO}_{2}+\mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow$ |
| (III) $\mathrm{BaCl}_{2}$ |
(R) $\mathrm{Ca}(\mathrm{OH})_{2}+\mathrm{MgCl}_{2} \rightarrow$ |
| (IV) $\mathrm{CaCO}_{3}$ |
(S) $\mathrm{BaO}_{2}+\mathrm{HCl} \rightarrow$ |
| (T) $\mathrm{Ca}\left(\mathrm{HCO}_{3}\right)_{2}+\mathrm{Ca}(\mathrm{OH})_{2} \rightarrow$ |
Match each compound in LIST-I with its formation reaction(s) in LIST-II, and choose the correct option
- AI $\rightarrow$ Q; II $\rightarrow$ P; III $\rightarrow$ S; IV $\rightarrow$ R
- BI $\rightarrow$ T; II $\rightarrow$ P; III $\rightarrow$ Q; IV $\rightarrow$ R
- CI $\rightarrow$ T; II $\rightarrow$ R; III $\rightarrow$ Q; IV $\rightarrow$ P
- DI $\rightarrow$ Q; II $\rightarrow$ R; III $\rightarrow$ S; IV $\rightarrow$ P
✓ Correct answer: D
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