$200\,\mathrm{mL}$ of an aqueous solution of a protein contains its $1.26\,\mathrm{g}$. The osmotic pressure of this solution at $300\,\mathrm{K}$ is found to be $2.57\times10^{-3}\,\mathrm{bar}$. The molar mass of protein will be $(R=0.083\,\mathrm{L\,bar\,mol^{-1}\,K^{-1}})$
- A$31011\,\mathrm{g\,mol^{-1}}$
- B$61038\,\mathrm{g\,mol^{-1}}$
- C$51022\,\mathrm{g\,mol^{-1}}$
- D$122044\,\mathrm{g\,mol^{-1}}$
✓ Correct answer: B
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