$20\,\mathrm{mL}$ of $0.2\,\mathrm{M}\,\mathrm{Al_{2}(SO_{4})_{3}}$ is mixed with $20\,\mathrm{mL}$ of $6.6\,\mathrm{M}\,\mathrm{BaCl_{2}}$, the concentration of $\mathrm{Cl^{-}}$ ion in solution is
- A$0.2\,\mathrm{M}$
- B$6.6\,\mathrm{M}$
- C$0.02\,\mathrm{M}$
- D$0.06\,\mathrm{M}$
✓ Correct answer: B
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