$\int_0^3\left(\sin \left(\frac{\pi}{3} x\right)-\cos \left(\frac{\pi}{3} x\right)\right) d x=$
- A
$\frac{-6}{\pi}$
- B
0
- C
$\frac{-3}{\pi}$
- D
$\frac{6}{\pi}$
✓ Correct answer: D
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NewNcert › mathematics › Definite Integration
$\int_0^3\left(\sin \left(\frac{\pi}{3} x\right)-\cos \left(\frac{\pi}{3} x\right)\right) d x=$
$\frac{-6}{\pi}$
0
$\frac{-3}{\pi}$
$\frac{6}{\pi}$
Want the full step-by-step reasoning?
Question ID #183979 · NewNcert