$$ \text { If } 6^{\text {th }} \text { term of a geometric progression is }-\frac{1}{32} \text { and } 9^{\text {th }} \text { term is } \frac{1}{256} \text { then } r \text { is } $$
- A2
- B$$ -\frac{1}{2} $$
- C$$\frac{1}{2} $$
- D$$-2$$
✓ Correct answer: B
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