The distance of the point (1, 1, 9) from the point of intersection of the line
$${{x - 3} \over 1} = {{y - 4} \over 2} = {{z - 5} \over 2}$$
and the plane x + y + z = 17 is :
- A$$19\sqrt 2 $$
- B$$2\sqrt {19} $$
- C38
- D$$\sqrt {38} $$
✓ Correct answer: D
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