The energy density in a parallel plate capacitor is given as \(1.8\times10^{-9}\,\mathrm{J\,m^{-3}}\). The value of the electric field in the region between the plates is: \((\varepsilon_0=9\times10^{-12})\)
- A\(6.6\,\mathrm{N\,C^{-1}}\)
- B\(20\,\mathrm{N\,C^{-1}}\)
- C\(66\,\mathrm{N\,C^{-1}}\)
- D\(2\,\mathrm{N\,C^{-1}}\)
✓ Correct answer: B
Want the full step-by-step reasoning?