The expression $((p \wedge q) \vee(p \vee \sim q)) \wedge(\sim p \wedge \sim q)$ is equivalent to
- A$\mathrm{p} \wedge \mathrm{q}$
- B$\mathrm{p} \vee \sim \mathrm{q}$
- C$\mathrm{p} \wedge \sim \mathrm{q}$
- D$(\sim p) \wedge(\sim q)$
✓ Correct answer: D
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