The formation of the oxide ion O²⁻(g), from oxygen atom requires first an exothermic and then an endothermic step as shown below: O(g) + e⁻ → O⁻(g); ΔegH = −141 kJ mol⁻¹ O⁻(g) + e⁻ → O²⁻(g); ΔegH = +780 kJ mol⁻¹ Thus process of formation of O²⁻ in gas phase is unfavourable even though O²⁻ is isoelectronic with neon. It is due to the fact that
- AElectron repulsion outweighs the stability gained by achieving noble gas configuration
- BO⁻ ion has comparatively smaller size than oxygen atom
- COxygen is more electronegative
- DAddition of electron in oxygen results in larger size of the ion.
✓ Correct answer: A
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