The general solution of the differential equation $\frac{d y}{d x}=\frac{2 x-3 y+4}{3 x+2 y-7}$ is
- A
$x^2+y^2=3 x y+y+C$
- B
$(2 x-3 y)^2+(3 x+2 y)^2=C$
- C
$x^2+y^2+3 x y-4 x-7 y+C=0$
- D
$x^2-3 x y-y^2+4 x+7 y+C=0$
✓ Correct answer: D
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