The integral $$\int {{{dx} \over {{x^2}{{\left( {{x^4} + 1} \right)}^{3/4}}}}} $$ equals :
- A$$ - {\left( {{x^4} + 1} \right)^{{1 \over 4}}} + c$$
- B$$ - {\left( {{{{x^4} + 1} \over {{x^4}}}} \right)^{{1 \over 4}}} + c$$
- C$$ {\left( {{{{x^4} + 1} \over {{x^4}}}} \right)^{{1 \over 4}}} + c$$
- D$$ {\left( {{x^4} + 1} \right)^{{1 \over 4}}} + c$$
✓ Correct answer: B
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