The pH of pure water at $80^{\circ} \mathrm{C}$ is
- A
7.0
- B
$\infty$
- C
$>7.0$
- D
$<7.0$
✓ Correct answer: D
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NewNcert › Chemistry › Equilibrium
The pH of pure water at $80^{\circ} \mathrm{C}$ is
7.0
$\infty$
$>7.0$
$<7.0$
Want the full step-by-step reasoning?
Question ID #181835 · NewNcert