The second overtone of an open pipe has the same frequency as the first overtone of a closed pipe of length '$$L$$'. The length of the open pipe will be
- A$$\frac{\mathrm{L}}{2}$$
- B$$\mathrm{L}$$
- C$$2 \mathrm{~L}$$
- D$$4 \mathrm{~L}$$
✓ Correct answer: C
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