The solution of the equation $x^2 y-x^3 \frac{\mathrm{~d} y}{\mathrm{~d} x}=y^4 \cos x$, where $y(0)=1$, is
- A$y^3=3 x^2 \sin x$
- B$x^3=3 y^3 \sin x$
- C$x^3=y^3 \sin x$
- D$y^3=4 x^3 \sin x$
✓ Correct answer: B
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